Below is my standard response about this. As you will see, it touches
exactly on what you are doing and why it does not work and what you need to
do:
What does not work has nothing really to do with RS but has to do with Stored
Procedures in SQL Server. You cannot do the following in a stored procedure.
Let's say you have a Parameter called @MyParams
Now you can map that parameter to a multi-value parameter but if in your
stored procedure you try to do this:
select * from sometable where somefield in (@MyParams)
It will not work. Try it. Create a stored procedure and try to pass a
multi-value parameter to the stored procedure. It will not work.
What you can do is to have a string parameter that is passed as a multivalue
parameter and then change the string into a table.
This technique was told to me by SQL Server MVP, Erland Sommarskog
For example I have done this
inner join charlist_to_table(@STO,Default)f on b.sto = f.str
So note this is NOT an issue with RS, it is strictly a stored procedure
issue.
Here is the function:
CREATE FUNCTION charlist_to_table
(@list ntext,
@delimiter nchar(1) = N',')
RETURNS @tbl TABLE (listpos int IDENTITY(1, 1) NOT NULL,
str varchar(4000),
nstr nvarchar(2000)) AS
BEGIN
DECLARE @pos int,
@textpos int,
@chunklen smallint,
@tmpstr nvarchar(4000),
@leftover nvarchar(4000),
@tmpval nvarchar(4000)
SET @textpos = 1
SET @leftover = ''
WHILE @textpos <= datalength(@list) / 2
BEGIN
SET @chunklen = 4000 - datalength(@leftover) / 2
SET @tmpstr = @leftover + substring(@list, @textpos, @chunklen)
SET @textpos = @textpos + @chunklen
SET @pos = charindex(@delimiter, @tmpstr)
WHILE @pos > 0
BEGIN
SET @tmpval = ltrim(rtrim(left(@tmpstr, @pos - 1)))
INSERT @tbl (str, nstr) VALUES(@tmpval, @tmpval)
SET @tmpstr = substring(@tmpstr, @pos + 1, len(@tmpstr))
SET @pos = charindex(@delimiter, @tmpstr)
END
SET @leftover = @tmpstr
END
INSERT @tbl(str, nstr) VALUES (ltrim(rtrim(@leftover)),
ltrim(rtrim(@leftover)))
RETURN
END
GO
--
Bruce Loehle-Conger
MVP SQL Server Reporting Services